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2017-9-11:学习笔记
阅读量:6842 次
发布时间:2019-06-26

本文共 13744 字,大约阅读时间需要 45 分钟。

mysql练习题

一丶综合练习

  • 准备表
#准备表,记录#创建数据库 mysql> create database db1; #选择数据库 mysql> use db1; #导入数据 mysql> source init.sql文件所在路径 init.sql文件内容
1 /*  2  数据导入:  3  Navicat Premium Data Transfer  4   5  Source Server         : localhost  6  Source Server Type    : MySQL  7  Source Server Version : 50624  8  Source Host           : localhost  9  Source Database       : sqlexam 10  11  Target Server Type    : MySQL 12  Target Server Version : 50624 13  File Encoding         : utf-8 14  15  Date: 10/21/2016 06:46:46 AM 16 */ 17  18 SET NAMES utf8; 19 SET FOREIGN_KEY_CHECKS = 0; 20  21 -- ---------------------------- 22 --  Table structure for `class` 23 -- ---------------------------- 24 DROP TABLE IF EXISTS `class`; 25 CREATE TABLE `class` ( 26   `cid` int(11) NOT NULL AUTO_INCREMENT, 27   `caption` varchar(32) NOT NULL, 28   PRIMARY KEY (`cid`) 29 ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8; 30  31 -- ---------------------------- 32 --  Records of `class` 33 -- ---------------------------- 34 BEGIN; 35 INSERT INTO `class` VALUES ('1', '三年二班'), ('2', '三年三班'), ('3', '一年二班'), ('4', '二年九班'); 36 COMMIT; 37  38 -- ---------------------------- 39 --  Table structure for `course` 40 -- ---------------------------- 41 DROP TABLE IF EXISTS `course`; 42 CREATE TABLE `course` ( 43   `cid` int(11) NOT NULL AUTO_INCREMENT, 44   `cname` varchar(32) NOT NULL, 45   `teacher_id` int(11) NOT NULL, 46   PRIMARY KEY (`cid`), 47   KEY `fk_course_teacher` (`teacher_id`), 48   CONSTRAINT `fk_course_teacher` FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`tid`) 49 ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8; 50  51 -- ---------------------------- 52 --  Records of `course` 53 -- ---------------------------- 54 BEGIN; 55 INSERT INTO `course` VALUES ('1', '生物', '1'), ('2', '物理', '2'), ('3', '体育', '3'), ('4', '美术', '2'); 56 COMMIT; 57  58 -- ---------------------------- 59 --  Table structure for `score` 60 -- ---------------------------- 61 DROP TABLE IF EXISTS `score`; 62 CREATE TABLE `score` ( 63   `sid` int(11) NOT NULL AUTO_INCREMENT, 64   `student_id` int(11) NOT NULL, 65   `course_id` int(11) NOT NULL, 66   `num` int(11) NOT NULL, 67   PRIMARY KEY (`sid`), 68   KEY `fk_score_student` (`student_id`), 69   KEY `fk_score_course` (`course_id`), 70   CONSTRAINT `fk_score_course` FOREIGN KEY (`course_id`) REFERENCES `course` (`cid`), 71   CONSTRAINT `fk_score_student` FOREIGN KEY (`student_id`) REFERENCES `student` (`sid`) 72 ) ENGINE=InnoDB AUTO_INCREMENT=53 DEFAULT CHARSET=utf8; 73  74 -- ---------------------------- 75 --  Records of `score` 76 -- ---------------------------- 77 BEGIN; 78 INSERT INTO `score` VALUES ('1', '1', '1', '10'), ('2', '1', '2', '9'), ('5', '1', '4', '66'), ('6', '2', '1', '8'), ('8', '2', '3', '68'), ('9', '2', '4', '99'), ('10', '3', '1', '77'), ('11', '3', '2', '66'), ('12', '3', '3', '87'), ('13', '3', '4', '99'), ('14', '4', '1', '79'), ('15', '4', '2', '11'), ('16', '4', '3', '67'), ('17', '4', '4', '100'), ('18', '5', '1', '79'), ('19', '5', '2', '11'), ('20', '5', '3', '67'), ('21', '5', '4', '100'), ('22', '6', '1', '9'), ('23', '6', '2', '100'), ('24', '6', '3', '67'), ('25', '6', '4', '100'), ('26', '7', '1', '9'), ('27', '7', '2', '100'), ('28', '7', '3', '67'), ('29', '7', '4', '88'), ('30', '8', '1', '9'), ('31', '8', '2', '100'), ('32', '8', '3', '67'), ('33', '8', '4', '88'), ('34', '9', '1', '91'), ('35', '9', '2', '88'), ('36', '9', '3', '67'), ('37', '9', '4', '22'), ('38', '10', '1', '90'), ('39', '10', '2', '77'), ('40', '10', '3', '43'), ('41', '10', '4', '87'), ('42', '11', '1', '90'), ('43', '11', '2', '77'), ('44', '11', '3', '43'), ('45', '11', '4', '87'), ('46', '12', '1', '90'), ('47', '12', '2', '77'), ('48', '12', '3', '43'), ('49', '12', '4', '87'), ('52', '13', '3', '87'); 79 COMMIT; 80  81 -- ---------------------------- 82 --  Table structure for `student` 83 -- ---------------------------- 84 DROP TABLE IF EXISTS `student`; 85 CREATE TABLE `student` ( 86   `sid` int(11) NOT NULL AUTO_INCREMENT, 87   `gender` char(1) NOT NULL, 88   `class_id` int(11) NOT NULL, 89   `sname` varchar(32) NOT NULL, 90   PRIMARY KEY (`sid`), 91   KEY `fk_class` (`class_id`), 92   CONSTRAINT `fk_class` FOREIGN KEY (`class_id`) REFERENCES `class` (`cid`) 93 ) ENGINE=InnoDB AUTO_INCREMENT=17 DEFAULT CHARSET=utf8; 94  95 -- ---------------------------- 96 --  Records of `student` 97 -- ---------------------------- 98 BEGIN; 99 INSERT INTO `student` VALUES ('1', '男', '1', '理解'), ('2', '女', '1', '钢蛋'), ('3', '男', '1', '张三'), ('4', '男', '1', '张一'), ('5', '女', '1', '张二'), ('6', '男', '1', '张四'), ('7', '女', '2', '铁锤'), ('8', '男', '2', '李三'), ('9', '男', '2', '李一'), ('10', '女', '2', '李二'), ('11', '男', '2', '李四'), ('12', '女', '3', '如花'), ('13', '男', '3', '刘三'), ('14', '男', '3', '刘一'), ('15', '女', '3', '刘二'), ('16', '男', '3', '刘四');100 COMMIT;101 102 -- ----------------------------103 --  Table structure for `teacher`104 -- ----------------------------105 DROP TABLE IF EXISTS `teacher`;106 CREATE TABLE `teacher` (107   `tid` int(11) NOT NULL AUTO_INCREMENT,108   `tname` varchar(32) NOT NULL,109   PRIMARY KEY (`tid`)110 ) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8;111 112 -- ----------------------------113 --  Records of `teacher`114 -- ----------------------------115 BEGIN;116 INSERT INTO `teacher` VALUES ('1', '张磊老师'), ('2', '李平老师'), ('3', '刘海燕老师'), ('4', '朱云海老师'), ('5', '李杰老师');117 COMMIT;118 119 SET FOREIGN_KEY_CHECKS = 1;
init.sql文件内容
  •  练习题题目 
1、查询所有的课程的名称以及对应的任课老师姓名
1 #sql语句 2 select cname,tname from course left join teacher on course.teacher_id=teacher.tid; 3 #运行结果 4 +-------+------------+ 5 | cname | tname      | 6 +-------+------------+ 7 | 生物  | 张磊老师   | 8 | 物理  | 李平老师   | 9 | 体育  | 刘海燕老师 |10 | 美术  | 李平老师   |11 +-------+------------+12 4 rows in set (0.00 sec)
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2、查询学生表中男女生各有多少人
1 #sql语句 2 select gender,count(sid) from student group by gender; 3 #运行结果 4 +--------+------------+ 5 | gender | count(sid) | 6 +--------+------------+ 7 | 女     |          6 | 8 | 男     |         10 | 9 +--------+------------+10 2 rows in set (0.00 sec)
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3、查询物理成绩等于100的学生的姓名
1 #sql语句 2 select sname from student where sid in 3 (select student_id from score 4 where course_id = 5  (select cid from course where cname='物理') 6 and num=100); 7  8 #运行结果 9 +-------+10 | sname |11 +-------+12 | 张四  |13 | 铁锤  |14 | 李三  |15 +-------+16 3 rows in set (0.03 sec)
View Code
4、查询平均成绩大于八十分的同学的姓名和平均成绩
1 #sql语句 2 select student.sname,t1.平均成绩 from student inner join 3 (select student_id,avg(num) 平均成绩 4 from score group by student_id having avg(num) > 80) as t1 5 on student.sid=t1.student_id; 6  7 #运行结果 8 +-------+----------+ 9 | sname | 平均成绩 |10 +-------+----------+11 | 张三  |  82.2500 |12 | 刘三  |  87.0000 |13 +-------+----------+14 2 rows in set (0.04 sec)
View Code
5、查询所有学生的学号,姓名,选课数,总成绩
1 #sql语句 2 select student.sid,sname 学生名,选课数,总成绩 from student left join(select student_id,count(course_id) 选课数,sum(num) 总成绩 from score group by student_id) as t1on student.sid=t1.student_id; 3  4 #运行结果 5 +-----+--------+--------+--------+ 6 | sid | 学生名 | 选课数 | 总成绩 | 7 +-----+--------+--------+--------+ 8 |   1 | 理解   |      3 |     85 | 9 |   2 | 钢蛋   |      3 |    175 |10 |   3 | 张三   |      4 |    329 |11 |   4 | 张一   |      4 |    257 |12 |   5 | 张二   |      4 |    257 |13 |   6 | 张四   |      4 |    276 |14 |   7 | 铁锤   |      4 |    264 |15 |   8 | 李三   |      4 |    264 |16 |   9 | 李一   |      4 |    268 |17 |  10 | 李二   |      4 |    297 |18 |  11 | 李四   |      4 |    297 |19 |  12 | 如花   |      4 |    297 |20 |  13 | 刘三   |      1 |     87 |21 |  14 | 刘一   |   NULL |   NULL |22 |  15 | 刘二   |   NULL |   NULL |23 |  16 | 刘四   |   NULL |   NULL |24 +-----+--------+--------+--------+
View Code
6、 查询姓李老师的个数
1 #sql语句 2 select count(tid) from teacher where tname like '李%'; 3  4 #运行结果 5 +------------+ 6 | count(tid) | 7 +------------+ 8 |          2 | 9 +------------+10 1 row in set (0.00 sec)
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7、 查询没有报李平老师课的学生姓名
1 #sql语句 2 select sname from student where sid not in ( 3 select distinct student_id from score where course_id in ( 4 select cid from course where teacher_id=(select tid from teacher where tname='李平老师') 5 ) 6 ); 7  8 #运行结果 9 +-------+10 | sname |11 +-------+12 | 刘三  |13 | 刘一  |14 | 刘二  |15 | 刘四  |16 +-------+17 4 rows in set (0.02 sec)
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8、 查询物理课程比生物课程高的学生的学号
1 #sql语句 2 select t1.student_id from 3 (select student_id,num from score inner join course on score.course_id=course.cid 4  where course.cname='物理') as t1 5  inner join 6 (select student_id,num from score inner join course on score.course_id=course.cid 7 where course.cname='生物') as t2 8 on t1.student_id=t2.student_id 9 where t1.num > t2.num10 ;11 12 #运行结果13 +------------+14 | student_id |15 +------------+16 |          6 |17 |          7 |18 |          8 |19 +------------+20 3 rows in set (0.00 sec)
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9、 查询没有同时选修物理课程和体育课程的学生姓名
1 #sql语句 2 select sname from student where sid in ( 3 select student_id from score inner join course 4 on course.cname in ('物理','体育') and course.cid=score.course_id 5 group by student_id having count(course_id) !=2 6 ); 7  8 #运行结果 9 +-------+10 | sname |11 +-------+12 | 理解  |13 | 钢蛋  |14 | 刘三  |15 +-------+16 3 rows in set (0.04 sec)
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10、查询挂科超过两门(包括两门)的学生姓名和班级名字
1 #sql语句 2 select t2.sname,class.caption from 3 (select sname,class_id from student inner join ( 4 select student_id from score 5 where num < 60 group by student_id having count(course_id) >=2 6 ) as t1 7 on student.sid=t1.student_id) as t2 8 inner join class 9 on class.cid = t2.class_id;10 11 #运行结果12 +-------+----------+13 | sname | caption  |14 +-------+----------+15 | 理解  | 三年二班 |16 +-------+----------+17 1 row in set (0.00 sec)
View Code
11 、查询选修了所有课程的学生姓名
1 #sql语句 2 select sname from student inner join 3 ( 4 select student_id from score group by student_id having count(course_id) = (select count(cid) from course) 5 ) t1 6 on t1.student_id = student.sid 7 ; 8 #运行结果 9 +-------+10 | sname |11 +-------+12 | 张三  |13 | 张一  |14 | 张二  |15 | 张四  |16 | 铁锤  |17 | 李三  |18 | 李一  |19 | 李二  |20 | 李四  |21 | 如花  |22 +-------+23 10 rows in set (0.00 sec)
View Code
12、查询李平老师教的课程的所有成绩记录
1 #sql语句 2 select student_id,course_id,num from score inner join 3 ( 4 select cid from course inner join teacher on teacher.tname='李平老师' and teacher.tid=course.teacher_id 5 ) as t1 6 on t1.cid=score.course_id; 7  8 #运行结果 9 +------------+-----------+-----+10 | student_id | course_id | num |11 +------------+-----------+-----+12 |          1 |         2 |   9 |13 |          3 |         2 |  66 |14 |          4 |         2 |  11 |15 |          5 |         2 |  11 |16 |          6 |         2 | 100 |17 |          7 |         2 | 100 |18 |          8 |         2 | 100 |19 |          9 |         2 |  88 |20 |         10 |         2 |  77 |21 |         11 |         2 |  77 |22 |         12 |         2 |  77 |23 |          1 |         4 |  66 |24 |          2 |         4 |  99 |25 |          3 |         4 |  99 |26 |          4 |         4 | 100 |27 |          5 |         4 | 100 |28 |          6 |         4 | 100 |29 |          7 |         4 |  88 |30 |          8 |         4 |  88 |31 |          9 |         4 |  22 |32 |         10 |         4 |  87 |33 |         11 |         4 |  87 |34 |         12 |         4 |  87 |35 +------------+-----------+-----+36 23 rows in set (0.00 sec)
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13、查询每门课程被选修的次数
1 #sql语句 2 select course.cname,选修人数 from course inner join 3 ( 4 select course_id,count(student_id) as 选修人数 from score group by course_id 5 ) as t1 6 on t1.course_id=course.cid 7 ; 8  9 #运行结果10 +-------+----------+11 | cname | 选修人数 |12 +-------+----------+13 | 生物  |       12 |14 | 物理  |       11 |15 | 体育  |       12 |16 | 美术  |       12 |17 +-------+----------+18 4 rows in set (0.00 sec)
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14、查询之选修了一门课程的学生姓名和学号
1 #sql语句 2 select sid,sname from student inner join 3 ( 4 select student_id from score group by student_id having count(course_id)=1 5 ) t1 6 on t1.student_id = student.sid; 7  8 #运行结果 9 +-----+-------+10 | sid | sname |11 +-----+-------+12 |  13 | 刘三  |13 +-----+-------+14 1 row in set (0.00 sec)
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15、查询所有学生考出的成绩并按从高到低排序(成绩去重)
1 #sql语句 2 select distinct num from score order by num desc; 3  4 #运行结果 5 +-----+ 6 | num | 7 +-----+ 8 | 100 | 9 |  99 |10 |  91 |11 |  90 |12 |  88 |13 |  87 |14 |  79 |15 |  77 |16 |  68 |17 |  67 |18 |  66 |19 |  43 |20 |  22 |21 |  11 |22 |  10 |23 |   9 |24 |   8 |25 +-----+26 17 rows in set (0.00 sec)
View Code
16、查询平均成绩大于85的学生姓名和平均成绩
1 #sql语句 2 select student.sname,avg_num from student inner join 3 ( 4 select student_id,avg(num) as avg_num from score group by student_id having avg(num) > 85 5 ) t1 6 on student.sid=t1.student_id 7 ; 8  9 #运行结果10 +-------+---------+11 | sname | avg_num |12 +-------+---------+13 | 刘三  | 87.0000 |14 +-------+---------+15 1 row in set (0.00 sec)
View Code
17、查询生物成绩不及格的学生姓名和对应生物分数
1 #sql语句 2 select student.sname,t1.num from student inner join 3 ( 4 select student_id,num from score 5 where course_id=(select cid from course where cname='生物') and num < 60 6 ) t1 7 on t1.student_id=student.sid; 8  9 #运行结果10 +-------+-----+11 | sname | num |12 +-------+-----+13 | 理解  |  10 |14 | 钢蛋  |   8 |15 | 张四  |   9 |16 | 铁锤  |   9 |17 | 李三  |   9 |18 +-------+-----+
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18、查询在所有选修了李平老师课程的学生中,这些课程(李平老师的课程,不是所有课程)平均成绩最高的学生姓名
1 #sql语句 2  3 select sname from student where sid = 4 ( 5 select student_id from score where course_id in 6 ( 7 select cid from course inner join teacher on teacher.tname='李平老师' and course.teacher_id=teacher.tid 8 ) 9 group by student_id10 order by avg(num) desc11 limit 112 );13 14 #运行结果15 +-------+16 | sname |17 +-------+18 | 张四  |19 +-------+20 1 row in set (0.00 sec)
View Code

 

  

Study Hard And Make Progress Every Day!

 

转载于:https://www.cnblogs.com/De-Luffy/p/7505215.html

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